Electric field / charged plates question.

AI Thread Summary
The discussion revolves around a physics assignment involving electric fields and charged plates, where the user is struggling with their calculations and receiving incorrect feedback from the assignment platform. They have calculated the time a charged particle spends between the plates and derived the vertical acceleration using the second equation of motion. The user arrives at a charge value of 2.54 * 10^-14 C but believes this is incorrect. Other participants suggest re-evaluating the vertical acceleration value, indicating that there may be an error in the calculations. The user seeks assistance in identifying any mistakes in their approach.
frasifrasi
Messages
276
Reaction score
0
I have this as an online assignment and think I have the wrong answer, but the site is telling me the result is wrong and takes a percentage off my grade each time i send a wrong submission.

I am just posting an image link because that way you guys can see the picture:

http://img142.imageshack.us/my.php?image=screenhunter003xp5qz5.png

Here is what I have so far:


t = length of plates / horizontal velocity

= 2.20 * 10-2 m / 18.0 m/s = 1.22 * 10-3 s

In the same time, the drop must deflect by 'd' distance along vertical direction. By second equation of motion

d = uy * t + (1/2) * ay * t2

uy = initial velocity along vertical direction = 0

ay = acceleration along vertical axis.

=> 0.300 * 10-3 = 0 * t + 0.5 * ay * (1.22 * 10-3)2

ay = 3.0 * 10-4 / 1.49 * 10-6 = 2.01 * 102 m/s2

__________________________________________________________

F = q * E

by Newton's second law F = m * a

=> m * ay = q * E

q = m * ay / E = 1.0 * 10-11 * 2.01 * 102 / 7.90 * 104

q = 2.54 * 10-14 C

But this is wrong and the site won't give me a feedback. If anyone can help me out, I would be very thankful. : )
 
Physics news on Phys.org
frasifrasi said:
ay = 3.0 * 10-4 / 1.49 * 10-6 = 2.01 * 102 m/s2

__________________________________________________________

F = q * E

by Newton's second law F = m * a

=> m * ay = q * E

q = m * ay / E = 1.0 * 10-11 * 2.01 * 102 / 7.90 * 104

q = 2.54 * 10-14 C

But this is wrong and the site won't give me a feedback. If anyone can help me out, I would be very thankful. : )
Check your value for ay again.
 
I did, it is 2.01 *10^2. Sorry, when I pasted, all the carrot signs disappeared.

Is there anything wrong with any of the steps?

Thanks.
 
anyone?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top