Electric field due to charged rods

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SUMMARY

The discussion focuses on calculating the electric field at a point P due to a charged vertical rod. The relevant equation provided is E = (λL) / (4πε₀√(x² + L²/4)), where λ represents the linear charge density, L is the length of the rod, and ε₀ is the permittivity of free space. The condition x/(l/2) < 1 indicates that point P is within a specific distance from the rod's perpendicular bisector. Participants emphasize the importance of integrating the electric field contributions along the length of the rod to obtain the total electric field at point P.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with linear charge density (λ)
  • Knowledge of calculus, specifically integration techniques
  • Basic principles of electrostatics and permittivity (ε₀)
NEXT STEPS
  • Study the derivation of the electric field due to continuous charge distributions
  • Learn about the concept of line integrals in electrostatics
  • Explore the effects of varying charge densities on electric fields
  • Investigate the application of Gauss's law in calculating electric fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields generated by charged objects.

-EquinoX-
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Homework Statement



If I have a charged vertical rod and a point P which is distanced x from the perpendicular bisector of it. How do I find the electric field at P if x/(/l/2) < 1, where l is the length of the rod

Homework Equations


The Attempt at a Solution



I know that the equation of an electric field due to a charged rod at P is:

[tex]\frac{\lambda L}{(4 \pi \epsilon_0) * sqrt(x^2 + L^2/4)}[/tex]

I don't know how to proceed further
 
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I'd draw a diagram and write a formula for a uniform line of charge and evaluate the integral over the range of the coordinates for the length of the rod.
 

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