Electric field/equipotential field questions

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Equipotential lines and electric field lines in a parallel plate capacitor are discussed, emphasizing that equipotential surfaces are always perpendicular to field lines. The potential difference between the plates is given as 10V, with calculations suggesting an electric field strength of 500V/m at a distance of 0.02m from the second plate. The importance of sketching the electric field direction, which curves to maintain right angles with equipotential lines, is highlighted. The discussion includes visual representations to aid understanding. Overall, the relationship between electric fields and equipotential lines is clarified through calculations and sketches.
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Homework Statement

1. Sketch the equipotential lines and field lines between a parallel plate capacotor assumed to have infinite plate area.

2. If the distance between the plates is 0.1m, the potential of one plate is 0V and the potential of the second plate is 10V, what is the potential at a point 0.02m from the second plate?

The attempt at a solution

1. I'm pretty sure field lines would just be from one of the plates to the other, but I'm not sure about the equipotential lines.

2. Not sure how to do this one!
 
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1) Equipotential surfaces are always perpendicular to field lines.

2) \displaystyle \Delta V = E\cdot \Delta x (for a uniform electric field)
 
1. something like this? (solid = field, dashed = equipotential)

http://img252.imageshack.us/img252/3261/untitledwz6.png

2. 10 = E*0.02
E = 500V/m?
 
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Yeah, except equipotential lines are continuous.
 
cool, I've got one more question

For this one, I need to sketch the direction of the electric field. I know they have to be perpendicular to the equipotential lines drawn, so I'm guessing its going to sort of curve slightly to make a right angle with each of the equipotential lines like such?

http://img248.imageshack.us/img248/761/img0328aiu1lf4.jpg
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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