Electric field in a conductive solution

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Discussion Overview

The discussion revolves around understanding the behavior of electric fields in a conductive solution, specifically in the context of a device with two parallel platinum electrodes connected to a constant voltage supply. Participants explore the relationship between electric fields and current in conductive media, addressing questions about calculations and the nature of the electric field within the solution.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions how a constant electric field can exist if there is a current flowing in the conductive solution.
  • Another participant asserts that without an electric field, there can be no current in a conductive medium, citing the relationship J = σE, where J is current density and σ is conductivity.
  • A participant inquires whether the electric field can be calculated using E = V/d and if it remains constant if the voltage does not change, while also asking about the significance of the current flowing between the plates.
  • Responses indicate that E = V/d can be approximated under certain conditions, specifically when the plate separation is small compared to the plates' dimensions.
  • Concerns are raised about the electric field being far from constant due to spatial variations within the conductive solution, despite not being time-varying.
  • One participant discusses the need for a good enough relation for the electric field, suggesting that the geometry of the plates affects the electric field distribution and referencing Gauss' law for further exploration.
  • Another participant provides a mathematical expression for the electric field between charged disks and discusses the implications of finite plate sizes on the electric field and voltage potential.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the electric field in the conductive solution, particularly regarding its constancy and the impact of spatial variations. There is no consensus on a definitive model or calculation method, and multiple competing perspectives remain throughout the discussion.

Contextual Notes

Limitations include assumptions about the uniformity of the electric field and the dependence on the geometry of the electrodes. The discussion highlights the complexity of accurately modeling the electric field in a conductive medium.

Who May Find This Useful

This discussion may be of interest to those studying electrostatics, conductive materials, and the behavior of electric fields in various geometrical configurations, particularly in experimental or applied physics contexts.

phd_to_be
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Hi all
I am reading an article and I need some help to understand it.

They describe a device they made in which there are 2 platinum flat electrodes connected to a constant voltage supply. The electrode are placed parallel to each other in a conductive solution (water with some salts).
They say there is a constant electric field between the electrodes.

How can it be? if there is a current (and there is a current, they reported it) why should there be an EF?
 
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phd_to_be said:
How can it be? if there is a current (and there is a current, they reported it) why should there be an EF?

You have that the wrong way around actually. Without an electric field there can be NO current in a conductive medium.

The current density is in fact proportional to the electric field,

J = \sigma \, E

Where \sigma is the medium's conductivity.
 
Last edited:
uart said:
The current density is in fact proportional to the electric field,

J = \sigma \, E
Where \sigma is the medium's conductivity.

So can I calculate the electric field by E=V/d, making it constant if the voltage doesn't change?
Can I ignore the current flowing between the plates?
Does this current change over time?


many question today :shy:
 
phd_to_be said:
So can I calculate the electric field by E=V/d, making it constant if the voltage doesn't change?
Yes you can approximate it as E=V/d if the plate separation is small compared to the plates linear dimensions.

Can I ignore the current flowing between the plates?
That depends on what you're doing. Why do you want to ignore it?

Does this current change over time?
Only if the voltage or the conductivity of the medium or positioning of the electrodes changes.
 
uart said:
Yes you can approximate it as E=V/d if the plate separation is small compared to the plates linear dimensions.

the plates are 17*5 mm = 85mm2
the distance between the plates is 50mm

can I approximate it as E=V/d?
 
phd_to_be said:
the plates are 17*5 mm = 85mm2
the distance between the plates is 50mm

can I approximate it as E=V/d?

Not really. The E field will be far from constant in the sense that it will vary quite a lot at different points within the conductive solution. That is, not time varying, but definitely having significant spatial variations.
 
what do you think is a good enougth relation?
 
phd_to_be said:
what do you think is a good enougth relation?

The equation for a field between 2 plates is an approximation based on the geometry. It can be found by approximating the plates as charged disks to find the electric field of each, and then applying symmetry with Gauss' law to get the field between them. Think if the plates are infinite, then any point on the plate is the same as another, but if they are finite then going on the edge or the plate will have different charge than going in the center of the plate, and this will all change at different distances between the plates.

The electric field of a charged disks with radius R at a distance z from the plate is derived to be:

E = \frac{\sigma}{2\epsilon_{0}}(1-\frac{z}{\sqrt{z^2+R^2}})
so when z is finite and R approaches infinity, you get a constant electric field independent of distance. Applying Gauss' planar symmetry to find the electric field between the two plates makes the 2 cancel out.

Then the voltage potential is simply the integral of this E field over a distance. If you use finite values of R and z, you will have a different solution to the integral, and that is your clue to finding a good enough relation. I won't do the work, and you might need to modify the stuff I said, but I think that will put you in the right direction.

The stuff is pretty basic, and if you need to read about this explanation, I get this information from "fundamentals of physics" by halliday,resnick,walker.
 
thanks.
I will read more :-)
 

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