yevi
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A half spherical shell as seen in the picture.
[URL=http://img219.imageshack.us/my.php?image=picnw3.jpg][PLAIN]http://img219.imageshack.us/img219/3424/picnw3.th.jpg[/URL][/PLAIN]
charged with surface density \sigma(\theta)=\sigma_{0}cos\theta
Need to find the Electric field in center of the axis.
As I see the direction of the electric field is the Z axis (because of the symmetric)
to find the Field I use:
dE_{z} = \frac{kdq}{R^2}
Finding q, q=2\pi R^{2}\sigma_{0}cos\theta?
[URL=http://img219.imageshack.us/my.php?image=picnw3.jpg][PLAIN]http://img219.imageshack.us/img219/3424/picnw3.th.jpg[/URL][/PLAIN]
charged with surface density \sigma(\theta)=\sigma_{0}cos\theta
Need to find the Electric field in center of the axis.
As I see the direction of the electric field is the Z axis (because of the symmetric)
to find the Field I use:
dE_{z} = \frac{kdq}{R^2}
Finding q, q=2\pi R^{2}\sigma_{0}cos\theta?
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