Electric field in the center of uniformly polarized cylinder

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SUMMARY

The discussion focuses on calculating the electric field intensity at the center of a uniformly polarized hollow dielectric cylinder with inner radius 'a', outer radius 'b', and height '2h'. The polarization vector, denoted as 'P', is normal to the bases of the cylinder, and the surrounding area is vacuum. The derived formula for the electric field intensity at point C is E = -Ph(1/(√a²+h²) - 1/(√b²+h²)) / ε0, where ε0 represents the permittivity of free space. The discussion highlights the relationship between polarization and electric field intensity in cylindrical geometries.

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  • Cylindrical geometry principles
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  • Knowledge of electric field calculations
  • Familiarity with permittivity of free space (ε0)
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Homework Statement


Hollow dielectric cylinder, with inner radius a, outer radius b, and height 2h is uniformly polarized by volume. Polarization vector is normal on the bases of a cylinder. Intensity of polarization vector is given, P. The surrounding area is vacuum. Calculate intensity of electric field in center of the cylinder (at point C)

Homework Equations


-Cylindrical geometry
-Polarization vector

The Attempt at a Solution


If approximated, intensity of electric field could be E= -P/ε0 (field between two oppositely charged planes). But, we don't know the exact values for dimensions of a cylinder. Could someone give a hint on this, I am stuck here for a while.

The result should be E= -Ph( 1/(√a2+h2)-1/(√b2+h2)) / ε0

Thanks for replies.
 

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Certain parts of the surface of the cylinder will have an effective surface charge density due to the polarization.
 

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