Electric field just beyond surface of proton

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SUMMARY

The electric field just beyond the surface of a proton, modeled as a uniform sphere of charge with a radius of 1.0 x 10-15 m, can be calculated using the equation E = (1/4πE0)(Q/r2). In this equation, E0 is the permittivity of free space, valued at 8.85 x 10-12 F/m, and Q represents the charge of the proton, which is equal in magnitude but opposite in sign to that of an electron. The solution is derived from Gauss's law, confirming the applicability of this approach for calculating electric fields around uniformly charged spheres.

PREREQUISITES
  • Understanding of Gauss's law
  • Familiarity with electric field equations
  • Knowledge of the properties of protons and electrons
  • Basic concepts of electrostatics
NEXT STEPS
  • Study the derivation of Gauss's law in electrostatics
  • Explore the implications of electric fields around charged spheres
  • Learn about the behavior of electric fields in different geometries
  • Investigate the relationship between charge, electric field, and potential energy
USEFUL FOR

Students of physics, particularly those studying electromagnetism, as well as educators and anyone interested in understanding electric fields related to charged particles like protons.

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Homework Statement



If a proton is considered a uniform ball of charge of radius 1.0x10-15m, what is the
electric field just beyond its surface?


Homework Equations



Gauss's law?

The Attempt at a Solution



I followed a problem in the book that found an equation for the electric field of a uniformly charged sphere. I treated the proton as a uniform sphere of charge, so that the same equation could be applied.

The equation was E = (1/4piE0)(Q/r^2)

*E0 is constant 8.85 x 10^-12.

So I just plugged in charge of electron and radius r of the proton.
 
Last edited:
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That looks fine. The result can of course be derived from Gauss' law. Remember that a proton has the same magnitude of charge as an electron but different sign.
 

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