Electric Field of a Capacitor with asymmetric dielectric

  • Thread starter Mikey789
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Hey guys,
if an question regarding a capacitor.
As seen in the picture there is a capacitor with an asymmetric dielectric e1 and e2.

http://img129.imageshack.us/img129/5999/kondensatorti8.jpg [Broken]

My question:
Who do I calculate the E-field of the capacitor?

thanks in advamce, help is appreciated!
Mike
 

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Answers and Replies

  • #2
berkeman
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Thread moved to homework help.

You generally need to show your own work in order for us to provide tutorial assistance. This is a tricky problem, so I'll offer one initial hint -- would it change the problem at all if you put in a floating metal plate at the green/beige boundary on the left and one on the green/beige boundary on the right? Try picturing that, and think about how capacitors in series add. Please show your work....
 
  • #3
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Thread moved to homework help.

You generally need to show your own work in order for us to provide tutorial assistance. This is a tricky problem, so I'll offer one initial hint -- would it change the problem at all if you put in a floating metal plate at the green/beige boundary on the left and one on the green/beige boundary on the right? Try picturing that, and think about how capacitors in series add. Please show your work....


Ok,
I know that the problem is in the middle....

If I just take the the left and the right part I have two capacitors in series.. which isn't a problem at all... the D-Fields are equal througout the capacitor and the E-Fields "change" at the boundary.. no problem here...

Now I take the middle part...
Depending on where I put the Gaussian surface I get inconsistent results... (see image 2)
In order to make the inconsistancy disapear I place electrons(+ or -) on the vertical part of the boundry.

->that would leave me with three capacitors in parallel

Is that correct?

Thanks
 

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  • #4
berkeman
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I would have split it in two. Why are you thinking of three?
 

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