Electric field - point of zero field

AI Thread Summary
To find the point where the electric field strength is zero between two charges, the relationship between the distances and charges must be established. The equation derived indicates that the zero field point is influenced by the magnitudes of the charges, with the distance from each charge varying based on their values. If both charges are positive, the zero point will be located between them, and the specific position can be calculated using the formula x = (sqrt(q2)/(sqrt(q1) + sqrt(q2)))d. The calculations suggest that if the charges are equal, the zero point is at the midpoint, x = d/2. The discussion emphasizes the importance of correctly applying the superposition principle and understanding the influence of charge magnitudes on the electric field.
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Homework Statement


Find a point on the line connecting two charges q_{1} and q_{1}
where the electric field strength is zero. These charges q_{1} and q_{1} at a distance of d.
NB - the charges can be of the same charge or different charge.

The Attempt at a Solution


I know the answer to be (say x is the distance):

x=\frac{\sqrt{q_{1}}}{\sqrt{q_{1}}\pm\sqrt{q_{2}}}d (1)

Right, for starters I assume that these charges are both positive? and I place a negative test charge to the right of the two charges, at a distance of x. This means that the test charge is at a distance d+x from the first charge.
Right, without revealing the in-between I reach a point where, by superposition

E_{1}-E_{2}=0

and dividing that by k

\frac{q_{1}}{(d+x)^{2}}-\frac{q_{2}}{x^{2}}=0

from where I reach the following by taking a square root of the above expression (by which I lose one solution?)

x=\frac{\sqrt{q_{2}}}{\sqrt{q_{1}}+\sqrt{q_{2}}}d

but that does not match up with the answer in the book. (1)
Especially the fact that q_{2} is in the top of the division, not q_{1}, the plus-minus part I don't mind.
 
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Right, for starters I assume that these charges are both positive?

If both the charges are positive, the point of zero electric field will in between the two charges, i.e. if x is the distance from one charge, d-x will be the distance from the other charge. The value of x depends on the charge from which the distance is measured.
 
If the charges are positive yes, even simply by using a mind experiment, the zero point is in between them. Depending on the charge of either q_{1} or q_{2}, the distance of the zero point from the first charge (say it is the starting point of the coordinate system) will vary by d-x...

And I don't know where I went wrong... I actually did the calculation before, but I assumed q_{1}=q_{2} and that gave me x= \frac{d}{2}, which makes sense when keeping my assumption in mind.

Thanks!
 
At neutral point

q1/x^2 = q2/(d-x)^2

Simplify and find the value of x.
 
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