An equilateral triangle with sides 66 m has charges +5 [tex] \mu C [/tex], -5 [tex] \mu C [/tex], and -9.3 [tex] \mu C [/tex] at its vertices and charge + 18.6 [tex] \mu C [/tex] at the midpoint on its side between the vertices with charges [tex] +5 and -5 \mu C [/tex]. What is the magnitude of the x-component of the electric field at point P, the point forming a second equilateral triangle with +5 [tex] \mu C and -5 \mu C [/tex]? Answer in units of N/C. Sorry I don't have a picture but it's 2 equilateral triangles that look like a mirror image of each other. First I drew a picture of what the electric fields would look like. The -9.3 and 18.6 [tex]\mu C [/tex] would not have a y-component, so I ignored those for now. so I found that k * 5 x 10^-6/ 66^2 * 33/66 = 5.17 and k * -5 x 10^-6 / 66^2 *57.2/66 = 8.95 (since it's absolute value of the charge) So E_x= 14.12... which isn't right.. help please?