(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A point charge q = 2.7 x 10^-6 C is placed at each corner of an equilateral triangle with sides of .11 m in length. What is the magnitude of the electric field at the midpoint of any of the 3 sides of the triangle.

2. Relevant equations

F = kqq/r^2

E = F/q

3. The attempt at a solution

F = k(2.7x10^-6)^2/.055^2

F = 21.66 N

Since there are two forces acting at this point

2 x 21.66 = 43.22 N is the total force.

E = F/q

43.22 N/2.7x10^-6C

= 16007407 N/C

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# Homework Help: Electric Field Question

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