Electric field strength at a point due to 3 charges

[Tesla In Person]

Homework Statement

Find the value of the charge placed at the point that makes the electric field 0.

Relevant Equations

Electric field: Kq /r^2

I got E. 13q as the answer. That is what i did: The electric field due to +q at origin 0 should equal the electric fields of charges -3q and the new charge placed at 2x. So applying the equation above like this; k*(q) / (2^2) = -3q*k + (k*C)/ 4 solving for C the new charge added, gives 13q. I don't know if it's correct because i don't have the answer to this question . Can you please check my working thanks.

 

[TSny]

Homework Statement:: Find the value of the charge placed at the point that makes the electric field 0.
Relevant Equations:: Electric field: Kq /r^2

I got E. 13q as the answer. That is what i did: The electric field due to +q at origin 0 should equal the electric fields of charges -3q and the new charge placed at 2x. So applying the equation above like this; k*(q) / (2^2) = -3q*k + (k*C)/ 4 solving for C the new charge added, gives 13q. I don't know if it's correct because i don't have the answer to this question . Can you please check my working thanks.

I think your answer is correct.

 

[TSny]

In order to make it easier for someone to follow your solution, you could show more steps. In particular, show why x does not appear in your equation and explain the choice of signs for the terms in your equation.

 

[PeroK]

I think your answer is correct.

It must be if it really is "Tesla".