Electric Field strength between 3 charges and directions

AI Thread Summary
The discussion focuses on calculating the net electric force on three point charges arranged in a line, with specific values for charge and separation distances. Participants express uncertainty about using vectors and the appropriate equations to solve the problem. Key equations mentioned include F = Eq and E = -(dv/dx), highlighting the need for a proper expression for electric field strength. There is a suggestion to reference external resources for better understanding. The conversation emphasizes the importance of grasping both magnitude and direction in electric field calculations.
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Homework Statement


Three point charges lie along a straight line as shown in the figure below, where
q1 = 6.36 µC, q2 = 1.57 µC and q3 = −1.82 µC.
The separation distances are d1 = 3.00 cm and d2 = 2.00 cm.
Calculate the magnitude and direction of the net electric force on each of the charges.

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Homework Equations





The Attempt at a Solution


I think I have to use vectors but I don't know how...
 
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Well, what equations do you have at hand to tackle this problem ?
 
BvU said:
Well, what equations do you have at hand to tackle this problem ?

I'm not very good with electricity...

F = Eq
E = -(dv/dx)
 
So you still need an expression for either V or ##\vec E##, right ?
 
I have been stuck on this question making no progress. Please help me go somewhere...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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