Electric field strength near a metal plate

AI Thread Summary
To find the electric field strength near a thin, square metal plate with a total charge of 21 μC, the formula E = σ/2ε₀ can be used, where σ is the surface charge density and ε₀ is the permittivity of free space. The surface charge density can be calculated by dividing the total charge by the area of the plate. The discussion highlights the importance of understanding the uniform distribution of charge on the plate, which can affect the calculation. One participant successfully calculated the electric field strength as 2.3 MN/C after converting units and applying the correct formula. The conversation emphasizes the need for clarity in problem statements to avoid confusion.
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Homework Statement


A total charge of 21 μC is applied to a thin, 1μm square metal plate 72 cm on a side.

Find the electric field strength near the plate's surface, far from the edges.
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Homework Equations


I think E = kq/r^2, but I really don't know.

The Attempt at a Solution


I am having a hard time figuring out where to start. I know I must find the electric field strength (i.e magnitude), but where do I begin and what do I do to find it. I just know that E = kq1q1/r^2, but there is no second charge so it must be kq1/r^2 correct? Do I use that or something else?
 
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No responses so far. Pressure's off if you've had your exam by now. Still want to address this one ?
 
There is a simple formula giving the E field near the surface of a charged medium such as a metal plate. Very simple.
 
BvU said:
No responses so far. Pressure's off if you've had your exam by now. Still want to address this one ?
My exam is today, but I managed to figure this one out. First converting the units into the proper units that I wanted to use I figured that for a plane its q/2a^2 and thus I entered to the units in and divided that by epsilon naught. I got 2.3 MN/C
 
Yes. My personal association is with the term Gaussian pillbox

A comment on the exercise: I miss the words 'uniformly distributed' ; that way good students easily get wrong-footed.
 
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