Electric field with constant direction

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The discussion revolves around a problem in Classical Electrodynamics involving a constant electric field defined by E_{x}=ax, E_{y}=0, and E_{z}=0, where a is a constant. The challenge is to understand how this electric field can maintain a constant direction despite a homogeneous charge density. It is suggested that the charged body could be modeled as an infinitely thick and high object, but the correctness of this assumption is questioned. The conversation highlights that while the charge density remains constant, the solution to the associated partial differential equation (PDE) div E=a is not unique and is influenced by boundary conditions. Ultimately, the boundary conditions at infinity play a crucial role in determining the electric field's behavior.
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I just started Classical Electrodynamics and stumbled upon a problem:

An electric field has this form:

E_{x}=ax ,E_{y}=0 ,E_{z}=0

where a is a constant.Find the density of the charge(ok that's easy).How do you explain that the field points towards a constant direction although the density of the charge is homogene?

Ok,so I though maybe the charged body is like mug with infinite thickness and an infinite hight.Is this correct?Is there a way to find the answer mathematically?
 
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The charge density is constant, but the solution to the PDE div E=a is not unique.
The solution for E also depends on the boundary conditions.
In this case the BC as x, y, and -->infinity determines E.
 
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