Electric Field Work on Moving Charge

AI Thread Summary
The work done by an electric field on a charge is not solely dependent on the distance traveled; it also depends on the path taken and the direction of the electric field. While the initial assumption was that doubling the distance would double the work done, this is incorrect without knowing the angle between the force and the path. The correct formula for work involves the cosine of the angle between the force and the displacement vector. Therefore, additional information about the paths and their orientation relative to the electric field is necessary to determine the work done accurately. The question is more complex than it initially appears.
david84
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Homework Statement



An electric field does 40 J of work on a charge moving from point A to point B in a straight line at a distance, d. If the charge moves through a different path from point C to point D at a distance of 2d, what is the work done on the charge?

Homework Equations



W=Fd

The Attempt at a Solution



I figure that because the distance is doubled, the work done will be doubled as well according to the work equation. So the total work done will be 40 J x 2 = 80 J. I'm not completely sure though cause I feel like I'm missing something. Is the question really this simple, and do I have the right answer? Thanks.
 
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david84 said:

Homework Statement



An electric field does 40 J of work on a charge moving from point A to point B in a straight line at a distance, d. If the charge moves through a different path from point C to point D at a distance of 2d, what is the work done on the charge?

Homework Equations



W=Fd

The Attempt at a Solution



I figure that because the distance is doubled, the work done will be doubled as well according to the work equation. So the total work done will be 40 J x 2 = 80 J. I'm not completely sure though cause I feel like I'm missing something. Is the question really this simple, and do I have the right answer? Thanks.
Welcome to PF David!

You do not have enough information to answer the question. We need to know the direction of the paths relative to the field E at all points in the path. This is because:

Work = W = \int \vec{F}\cdot d\vec{s} = \int |\vec{F}| |d\vec{s}|\cos\theta

over a given path, where \theta is the angle between the Force and the path.

AM
 
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