Electric Fields at Points A, B, C, and D: How Do They Compare?

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The discussion centers on the electric fields produced by two large sheets of charge, one positively and one negatively charged, and their effects at points A, B, C, and D. The electric field direction is consistently to the right, with magnitudes ranked as B>A=C>D. The electric force on a charged particle at points A and C is considered to be zero due to equal repulsion and attraction from the sheets, while points B and D experience equal forces due to their equidistant positions from the sheets. The uniform electric field between the plates means that the force on a test charge remains constant regardless of its position within that region. Ultimately, the discussion clarifies that the electric field is uniform between the plates, leading to consistent force experiences for test charges placed anywhere in that area.
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Homework Statement


Two very large sheets of charge are separated by a distance d. One sheet has a surface charge density +o and the other a surface charge density -o. A small region near the center of the sheets is shown.
1. Draw arrows on the diagram to indicate the direction of the electric fields at points A, B, C, and D
2. Compare the magnitudes of the electric fields at points A, B, C and D
3. How would the electric force exerted on a charged particle at point A compare to the electric force exerted on the same particle at point B? point C? point D?

Homework Equations


E = F/q


The Attempt at a Solution


1. All pointing to the right
2. B>A=C>D. Electric field is imagining putting +1C of charge; therefore it would repel the + charge and attract to the - charge
3. I have trouble on this question. I think that at points A and C, E-force would be 0 because the electric force from + and - repel. At point B and D, it would be the same because they are equidistant from the electrodes?
 

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It does not matter where are charge is placed in between the plates. The net force is always the same becuase the electric field is uniform between two parallel plates. If we drop a negative test charge in, the negative plate will repel it, while the positive plate attracts it. Even if its in the middle, it will be repelled by one plate and pulled by the other.
 
I thought electric field is always putting +1C of charge at the places on the points. Therefore, the closer it is to the positive side, the stronger the electric field, and the faster it would get repelled by the positive charge
 
Yea, youre right. Its the force experienced by placing a test charge at a point in space. But it seems like your diagram and the way its described would come out to be a uniform electric field. So no matter where the test charge, the force will always be the same.
 
Sorry, but I am just not getting this. E = k (q/r^2). As you can see, E depends on the distance between the charges acting on it. I know you're definitely right because the book says so, but it really did not explain much into it.
 
oh okay, i just got it from one of your replies ranger, thanks
 

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