Electric fields caused by multiple charges

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SUMMARY

The discussion focuses on determining the position along the x-axis where the electric field strength becomes zero due to a particle with charge +7.88 μC located at x = 3.00 m in a uniform electric field of 300 N/C. The relevant equation used is E = K*Q / r², where K is the electrostatic constant. The goal is to find a point where the electric fields from the charge and the uniform field cancel each other out, resulting in a net electric field of zero.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with Coulomb's Law
  • Knowledge of basic algebra for solving equations
  • Concept of superposition in electric fields
NEXT STEPS
  • Study the principles of superposition in electric fields
  • Learn how to apply Coulomb's Law in various configurations
  • Explore the concept of electric field lines and their implications
  • Investigate the effects of multiple charges on electric field strength
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Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields and their interactions with charged particles.

lacar213
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Homework Statement


A particle with charge +7.88 μC is placed at the fixed position x = 3.00 m in an electric field of uniform strength 300 N/C, directed in the positive x direction. Find the position on the x-axis where the electric field strength of the resulting configuration is zero.


Homework Equations


E= K*Q / r^2


The Attempt at a Solution


I set up the equation with E = 0 but I'm not sure how you can solve it now for R since e = 0
 
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Find a value for r such that E becomes equal and opposite to 300N/C ie a point where the 2 fields cancel to zero.
 

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