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Electric fields, distance, and potential difference

  1. Sep 17, 2008 #1
    1. The problem statement, all variables and given/known data

    The potential difference between the accelerating plates of a TV set is about 20 kV. If the distance between the plates is 1.0 cm, find the magnitude of the uniform electric field in the region between the plates.



    2. Relevant equations

    V=ED so E=V/D where E is the electric field and D is the distance between the plates



    3. The attempt at a solution

    I am soooo confused. I swear im just plugging in the numbers. since kv is 1000 v and cm is 1/100th of a m i did 20,000/.01 and that was wrong. I did this because they want the answer in N/C and i thought that conversion factor was right... any suggestions???
     
  2. jcsd
  3. Sep 17, 2008 #2

    Redbelly98

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    Your equation looks right to me. What did you get for a final answer? Did you include the units in your answer?
     
  4. Sep 17, 2008 #3
    yes the units are already written after the equation. I got 2.0*10^6. after going over everything it looks right to me...
     
  5. Sep 18, 2008 #4

    Redbelly98

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    Yes, looks right to me too. Weird.
     
  6. Sep 18, 2008 #5

    Defennder

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    What's the answer supposed to be?
     
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