Electric Fields in Coaxial Cables: Understanding Bound Charge Densities

AI Thread Summary
In coaxial cables, the charge density λ on the inner conductor is assumed to be equal in magnitude but opposite in sign on the outer shell due to the nature of electric fields and charge distribution. The presence of a dielectric material increases the capacitance, as indicated by the relationship between the relative permittivity (ε_r) and the bound charge densities resulting from polarization. However, the total charge remains unchanged, meaning that the polarization does not contribute to the overall charge density. This understanding clarifies the behavior of electric fields in coaxial cables with dielectrics. The discussion emphasizes the importance of recognizing the role of bound charge densities in this context.
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Homework Statement


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Homework Equations

The Attempt at a Solution


I understand all the calculations here - http://www.physicspages.com/2012/10/18/coaxial-cable-with-dielectric/
I have one issue that is bugging me though - if λ charge density is distributed over the inner conductor, why can it be assumed that the same -λ is distributed over the outer shell? Aren't there any bound charge densities involved here?

Thank you.
 
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With bound charge densities you mean the polarization ? That is involved. That's why (for ##\epsilon_r > 1##) C is greater than for the same coax without the dielectric. But the ##\lambda## are the same: polarization has no total charge.
 
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