Electric Flux Calculation for Oppositely Charged Circular Plates

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The discussion centers on calculating electric flux between two oppositely charged circular plates with a charge of ±1.0 nC, a radius of 5.00 cm, and a separation of 1.00 mm. Participants express confusion about applying Gauss's Law, noting that it typically involves closed surfaces, while this scenario involves an open surface. The definition of electric flux is crucial for understanding the problem, as it relates to the electric field and the area through which it passes. Additionally, it is suggested that the electric flux for a larger radius of 5.00 meters would yield similar results due to the uniformity of the electric field between the plates. Understanding these principles is essential for solving the homework problem effectively.
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Homework Statement


Two circular parallel metal plates are oppositely charged with q = ±1.0 nC. The two plates each have a radius of 5.00 cm and are separated by 1.00 mm. (a) Estimate the electric flux for a circular area of radius 5.00 cm sandwiched between the two plates. (b) Repeat for a circular area of radius 5.00 meters – the result would be essentially the same. Explain why this would be the case.

I don't know how to start. I thought that any charge outside a gauss surface is zero to that surface.
 
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This isn't really a Gauss's Law problem. Gauss's Law deals with flux through closed surfaces. Here, we have an open surface.

HINT: Let's start at the beginning. Can you state the definition of electric flux for me?
 
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