Electric Flux Density: 4.5Xe + .50MV/m

AI Thread Summary
To find the displacement flux density D given Xe=4.5 and E=0.50 MV/m, the equation D=ε0εrE is used, where εr=1+Xe. The calculation yields D=0.000024338 C/m^2, which is questioned as it does not match the expected answer format. The confusion arises regarding the unit conversion, as the expected result is in nC/m^2 or μC/m^2. Ultimately, the correct interpretation of the units leads to a final result of 24.338 μC/m^2.
DODGEVIPER13
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Homework Statement


Given Xe=4.5 and E=.50 MV/m find the displacement flux density

Homework Equations


D=ε0εrE
εr=1+Xe

The Attempt at a Solution


Using the equation above I get (8.85e-12)(5.5)(.50e6)=.000024338 C/m^2 which is not what the answers say they give it in nC which I can't see how they can do?
 
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Sorry they give it in nC/m^2
 
Actually looking at it the real units are μC/m^2
 
Should it be 24.338μC/m^2
 

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