Electric Flux through a Closed Hemisphere Question

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The problem involves calculating the electric flux through a closed hemisphere centered at the origin, with an infinite line of charge along the x-axis. The enclosed charge is determined to be λ multiplied by the length of the base circle, resulting in a flux equation of 2λa/ε. Clarification on whether the hemisphere is a closed surface is confirmed, as it is indeed a closed hemisphere. The orientation of the hemisphere is questioned, specifically whether its axis of symmetry aligns with the x-axis. Understanding these factors is crucial for correctly applying Gauss's law to find the electric flux.
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Homework Statement


An infinite line of charge is along the entire x-axis has a constant value for λ. A hemisphere is centered at the origin and has a base circle of radius a. What is the electric flux throught the hemisphere


Homework Equations



Flux = Q enclosed / ε

The Attempt at a Solution



Q enclosed must be λ* (2a) .. Thus, the answer should be 2λa/ε. Is this right or should we half it.. I mean would this be the same answer if the hemisphere was a full sphere. Thanks for helping!
 
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What's the orientation of the hemisphere? Is it just a hemisphere or is it a closed surface? (Gauss's law requires a closed surface.)
 
It is a closed hemisphere!..
 
ehabmozart said:
It is a closed hemisphere!..
Good. What is its orientation? Is its axis of symmetry parallel to the x-axis?
 

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