Electric Forcs and Work (Algebra based physics)

AI Thread Summary
To calculate the work done in moving two charges, the initial and final distances between the charges must be accurately determined. The user attempted to apply the formula F = kq/r but encountered issues with the distance calculation, leading to an incorrect force value. The work done is then calculated using W = F*d, but the user questions if potential energy concepts have been fully considered. Understanding the relationship between electric potential energy and work is crucial for solving this problem accurately. Clarifying these concepts may help resolve the user's confusion and lead to the correct answer.
Seikon85
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Charges q1=+7.15 x 10-05 C and q2=-7.80 x 10-04 C are placed at rest 71.5 cm apart. How much work must be done by an outside agent to move these charges slowly and steadily until they are 31.0 cm apart?

Ok so I tried a few things on my own, and got stuck. So I referred to a previous post from this morning for guidance:

http://answerboard.cramster.com/physics-topic-5-199660-0.aspx

however, I am still getting the wrong answer.


I am using F = kq/r initially. The r value i am using was obtained by figuring out the distance one charge moved. (.715-.31)/2. Then subtracting that distance from .715. So my r = .513m here.

I get F = 968J.

W = F*d = 968J * (.31m) = 300J.


Am I missing something obvious. Any insight?

Thanks.
 
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