Electric potential at a point due to two charges

AI Thread Summary
The discussion focuses on calculating the electric potential at a point due to two charges using the formula V=KQ/r. The user correctly calculated the potentials from each charge, obtaining 36,000V and 18,000V, leading to a total of 54,000V. A clarification was made that the question pertains to electric potential, not electric field, which is a vector quantity. The user acknowledged the oversight in reading the question and confirmed the final answer. This highlights the importance of understanding the distinction between electric potential and electric field in physics problems.
Schaus
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Homework Statement


What is the electric potential at P due to charges Q1 and Q2?
https://lh3.googleusercontent.com/tUDlHBQ52PYnzufzP-Kow958ph1wtMx-Ar2qhUvAIATr-otVU6ESS6vHnPpv8MNO2NQnII4SQjJ041O9YwGa0LjXHh_rJISBvX7Aoa1PPX7G-YSIQBH6mhyJh0zX2k40M6MceWdCGc7XEMUIT4cnvUqd2s2I6PFbFFBq9NAFftkITBAMNcpevIkdiR4BjYP03Ap0lDGHt3QsM1BNSY4eFannXQbq5WKipGUMk24d4yyewzh2lHph_kOBmCyF3oyTonsfD0hLdpTQeRL6_l4VdlAyFUCHmwcID8vVRNXImlVwsFdQRPO2ZjXog3Fj7HATJbqrhRPNI15vUO99Nn82a3oT26ogHn8jPK5CICvLk8eZZdYfPJuFUOJLCL4xw8_ZVLMZS8xdYw6y4KOg87pN642r8D3sewHjeJejKvtWFkOf6Th5M_kLOXMN2mkMasYc2PoF1rEYNnbyC13KaRZ7uFc9tnK6cDLdLBvAfbwZdjhQ50XZzoc9oK0mWvJIRkK9-rTOHDHlyAEYP8JHfyeSQp7Xg4LX5RA6m9ZFLFAJVDGFGTo1VafxTUlEzs9f-uCOJz6nkO2gQY0z1pcPk3K4NNgps-KCU2YKFkmbgiNmihdEbrtghvgN=w684-h241-no
upload_2016-12-23_14-51-15.png

Homework Equations


V=KQ1/r

The Attempt at a Solution


I used the above formula to...
(9.0 x 109)(4.0 x 10-6)/1 = 36000V
(9.0 x 109)(1.0 x 10-6)/0.5 = 18000V
Now the answer is 54000V and I'm just wondering if that's the answer because you take 36000J + 18000V = 54000V?
 
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Check the equation you're using for electric potential. The question asks for the potential, not the electric field (which would be a vector quantity).
 
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Wow I don't know how I missed the fact it said potential. I may need to take a break. Thanks for your help! I got the answer.
 
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