Electric Potential-finding unknown charge

  • Thread starter Thread starter abspeers
  • Start date Start date
  • Tags Tags
    Charge Electric
AI Thread Summary
The potential at the midpoint between two point charges is given as 7.52 V, with one charge known to be 1.11 x 10^-9 C and the distance between the charges being 0.91 m. The equation used to find the unknown charge involves the formula V = k [sum] (q/r), leading to an attempt that resulted in -7.3 x 10^-10 C, which was marked incorrect on Webassign. The discussion highlights confusion over the correctness of the calculation, as multiple peers have arrived at the same answer. It is suggested that the individual should consult their teacher for clarification on the problem.
abspeers
Messages
4
Reaction score
0

Homework Statement



The potential equals 7.52 V at the midpoint between two point charges that are 0.91 m apart. One of the charges is 1.11 x 10-9 C. Find the value of the other charge.

Homework Equations



V = k [sum] (q/r)

The Attempt at a Solution



7.52=k[(1.11 x 10-9 / 0.455m ) + ( x / 0.455m )]

This gives me -7.3x10^-10, which is incorrect, but I cannot think of any other way to approach this problem.
 
Physics news on Phys.org
Your approach is correct and the numbers match the approach. How do you know it is incorrect? Do you know the correct answer?
 
I am entering the answers in Webassign and it marked my answer as incorrect. I think there must be a mistake because no one I've showed it to has gotten a different answer.
 
It is time to ask your teacher. You might do everybody a favor.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top