Electric Potential Homework: Infinite Wire & Distance R

AI Thread Summary
The discussion revolves around calculating the electric potential at a distance r from an infinite conducting charged wire. The initial approach uses the electric field formula E = λ/(2πεr) and attempts to integrate it to find the potential, resulting in V(r) = -λ/(2πε) log(r). However, this method is flawed because it doesn't account for integrating from an element of the wire over the entire length, leading to potential undefined behavior. The confusion arises from the realization that integrating the potential from a line element results in complications due to its scalar nature. Ultimately, the challenge lies in correctly addressing the integration of the electric field to derive a valid expression for the potential.
chaoseverlasting
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Homework Statement



There is an infinite conducting charged metallic wire. What will the potential at a distance r from the wire be?



The Attempt at a Solution



I know that E=\frac{\lambda}{2\pi \epsilon r} and E=\frac{-dv}{dr}.

Integrating the expression for the electric field wrt r, V(r)=-\frac{\lambda}{2\pi \epsilon} logr

This, however, isn't the answer. Why?
 
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You should be integrating the field from an element of the wire from -inf to +inf.
 
Ouch. That would make it undefined at that point, right?
 
Assume you have linear charge density r, so the charge of a line element is r.dl. The electric field at point r is k.r.dl/(r^2+l^2).
 
I can figure out the expression for the electric field, but its the potential I had the question about. Wont it be undefined?
 
Rats, I misread the question. Integrating the potential of a line element blows up because it's a scalar. It really does look as if there's nothing you can differentiate to give the 1/r dependence.
 
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