Electric potential of electric dipole at large distance

AI Thread Summary
The discussion focuses on deriving the electric potential of an electric dipole at large distances. The relevant equation provided is V = (qa cos(theta))/(4 pi epsilon r^2), where 'a' represents the separation of the charges and 'r' is the distance from the dipole. Participants clarify that as the distance 'r' approaches infinity, the potential approaches zero, since the contributions from the positive and negative charges cancel each other out. The dipole moment is defined as qa, emphasizing its significance in the equation. Overall, the electric potential of an electric dipole at large distances is effectively zero.
blueyellow

Homework Statement



write down an expression for the electric potential of an electric dipole at a large distance

Homework Equations



V=(qa cos(theta))/(4 pi epsilon r^2)

The Attempt at a Solution



is 'r' the distance they are talking about or is it 'a'?
either way, if i substitute in a=infinity or r=infinity, the above equation just blows up
 
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hi blueyellow! :smile:

(have an infinity: ∫ and a theta: θ and a pi: π and an epsilon: ε and try using the X2 icon just above the Reply box :wink:)
blueyellow said:
is 'r' the distance they are talking about or is it 'a'?
either way, if i substitute in a=infinity or r=infinity, the above equation just blows up

a is the separation of the two ±q charges (so qa is the dipole moment)

(and 1/∞2 = 0 :wink:)
 
and you can also find it like this:

as r>>a ... so distance of point at r is approx same from both charge ie ≈ r

so V = kq/r + k(-q)/r = 0
 
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