Electric Potential problem escape veloctiy.

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SUMMARY

The discussion focuses on solving an electric potential problem related to escape velocity, specifically involving a proton's kinetic energy equating to electric potential energy (EPE). The participant attempts to derive the initial velocity (Vi) using the formula Vi = sqrt(2/m * ((K*1.5nC*e/.005m) + (K*1.5nC*e/.005m))). However, they encounter discrepancies in their results, suggesting that adjusting the equation by changing 2/m to 1/m and dividing the final answer by 2 yields more accurate results. The key takeaway is that accurately calculating the EPE is crucial, especially when the proton is positioned equidistantly between two equal charges.

PREREQUISITES
  • Understanding of electric potential energy (EPE) and kinetic energy (KE) concepts.
  • Familiarity with Coulomb's law and constants such as K (Coulomb's constant).
  • Basic knowledge of mechanics, particularly the relationship between mass, velocity, and energy.
  • Proficiency in algebraic manipulation of equations.
NEXT STEPS
  • Study the derivation of escape velocity in electrostatic contexts.
  • Learn about the implications of electric potential energy in multi-charge systems.
  • Explore the relationship between kinetic energy and electric potential energy in particle physics.
  • Review the principles of energy conservation in electric fields.
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism and energy conservation principles, as well as anyone solving problems related to electric potential and escape velocity.

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Homework Statement



http://www.phy.mtu.edu/~gagin/2200/textfiles/ph2200-ex2-f05.pdf
#23

Homework Equations



My attempt at the equation:
Vi = sqrt(2/m * ((K*1.5nC*e/.005m) + (K*1.5nC*e/.005m)))

The Attempt at a Solution



My equation gives me a value that is too large. Any help appreciated.

I noticed if I change the 2/m to 1/m and divide my final answer by 2 it is a value around the size of the answer...
 
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The kinetic energy must equal the electric potential energy (EPE) of the proton at the current position, which seems to be the approach one has taken.

Then one can determine the v from KE.

Getting the EPE correct is the key. The proton is equidistant between two equal charges.

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elepe.html
 

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