Electric Potential problem escape veloctiy.

[PhysicsGnome]

Homework Statement

http://www.phy.mtu.edu/~gagin/2200/textfiles/ph2200-ex2-f05.pdf
#23

Homework Equations

My attempt at the equation:
Vi = sqrt(2/m * ((K*1.5nC*e/.005m) + (K*1.5nC*e/.005m)))

The Attempt at a Solution

My equation gives me a value that is too large. Any help appreciated.

I noticed if I change the 2/m to 1/m and divide my final answer by 2 it is a value around the size of the answer...

 

[Astronuc]

The kinetic energy must equal the electric potential energy (EPE) of the proton at the current position, which seems to be the approach one has taken.

Then one can determine the v from KE.

Getting the EPE correct is the key. The proton is equidistant between two equal charges.

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elepe.html

 

[ogb p]

It looks like you are on the right track with your attempt at the equation. However, there are a few things that need to be clarified. Firstly, the equation should be written as V = sqrt(2qE/m), where V is the escape velocity, q is the charge of the particle, E is the electric potential, and m is the mass of the particle. Secondly, it seems like you have substituted the values for the charge and electric potential correctly, but the mass should be given in kilograms, not grams. Additionally, it is important to use the correct units for each quantity in the equation.

If you are still getting a value that is too large, it could be due to rounding errors or using approximate values for the constants. I would suggest using the exact values for the constants and carrying out the calculations with more significant figures to get a more accurate result. Additionally, it may be helpful to double check your units and make sure they are consistent throughout the equation.

I hope this helps and good luck with your homework!