Need help with Electric Potential problem.

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SUMMARY

The discussion revolves around solving an electric potential problem involving a proton and two point charges of 1.5nC each. The user is attempting to calculate the initial velocity (vi) using the formula vi = sqrt(2/m * ((K*1.5nC*e/.005m) + (K*1.5nC*e/.005m))). However, they are encountering issues with obtaining excessively large values. The correct approach involves considering the total energy of the proton, which is entirely potential energy when far from the charges, and applying the formula for electrical potential energy, -k(Q1)(Q2)/r, to evaluate the potential between the proton and one charge, then doubling it due to symmetry.

PREREQUISITES
  • Understanding of electric potential and potential energy concepts
  • Familiarity with Coulomb's Law and the constant k
  • Basic knowledge of kinetic and potential energy relationships
  • Ability to manipulate equations involving charge and distance
NEXT STEPS
  • Review the principles of electric potential energy and Coulomb's Law
  • Study the derivation and application of the formula -k(Q1)(Q2)/r
  • Learn about energy conservation in electric fields
  • Explore symmetrical charge distributions and their effects on electric potential
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone tackling problems related to electric potential and energy in electrostatics.

PhysicsGnome
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I was going over that mit open courseware stuff and I ran into a problem I'm having trouble with...

http://www.phy.mtu.edu/~gagin/2200/textfiles/ph2200-ex2-f05.pdf

#23

The equation I have for it is:

vi = sqrt(2/m * ((K*1.5nC*e/.005m) + (K*1.5nC*e/.005m)))

But I'm getting to large a value... I've been playing around with it but can't seem to get it.

Thanks for any help.
 
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First consider the proton between the charge and its total energy (it will be all potential). Then consider the particle very far away, such that it has zero potential energy, and all kinetic energy.
The formula for electrical potential energy is

-k(Q1)(Q2)/r

between any two point charges of charge Q1 and Q2, r the distance between them. We can evaluate the potential between the proton and one charge and multiply by two because the situation is symmetrical.
 

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