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Electrochemical Cell

  1. Dec 10, 2011 #1
    I built a cell with one side containing the solution 0.10 M CuSO4 with Cu(s) in it. The other side has 1 M NH3 and 0.05 M ZnSO4 with Zn(s) in it. The measured cell potential was 1.31.

    I am using the Nernst equation. I need to find the concentration of Zn^2+.

    E=E"-(0.059/2)logQ

    1.31 = 1.10 -(0.059/2) log Q

    Q = 7.61E-8

    I am confused about what Q is. I know its definition, but I am not sure about the reaction and which concentrations to use.
    Could someone help me out?
     
  2. jcsd
  3. Dec 13, 2011 #2

    Borek

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    Staff: Mentor

    On both sides you have metal electrode submerged in the solution of its own ions. In both cases reaction is identical (although metal is different).
     
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