1. May 5, 2006 #1

   Bladibla

   

   When we work out the E cell of with the electrode potential values of Zinc and copper (for example) Why does a positive E cell value indicate that the reaction is plausible?

    

   Bladibla, May 5, 2006
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3. May 6, 2006 #2

   Borek

   

   Staff: Mentor

   Matter of convention.

    

   Borek, May 6, 2006
4. May 6, 2006 #3

   Gokul43201

   

   Staff Emeritus

   Science Advisor

   Gold Member

   [tex]- \Delta G^0 = work~done ~at~constant~potential=E^0_{cell} \Delta Q [/tex]
   [tex]\Delta Q = nF [/tex]
   [tex]\implies \Delta G^0 =-nFE^0_{cell} [/tex]
   
   Of course, now this translates to another convention : that a negative free energy change tells you that the reaction is plausible. To make this more intuitive, it may help to go a step further.
   
   [tex]\Delta G^0 = -RT lnK [/tex]
   [tex]\Delta G^0 < 0 \implies lnK > 0 \implies K > 1 [/tex]

    

   Gokul43201, May 6, 2006

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