1. May 5, 2006 #1

   Bladibla

   

   When we work out the E cell of with the electrode potential values of Zinc and copper (for example) Why does a positive E cell value indicate that the reaction is plausible?

    

   Bladibla, May 5, 2006
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • Game over? Computer beats human champ in ancient Chinese game
   • • Simplifying solar cells with a new mix of materials
   • • Imaged 'jets' reveal cerium's post-shock inner strength
3. May 6, 2006 #2

   Borek

   

   Staff: Mentor

   Matter of convention.

    

   Borek, May 6, 2006
4. May 6, 2006 #3

   Gokul43201

   

   Staff Emeritus

   Science Advisor

   Gold Member

   [tex]- \Delta G^0 = work~done ~at~constant~potential=E^0_{cell} \Delta Q [/tex]
   [tex]\Delta Q = nF [/tex]
   [tex]\implies \Delta G^0 =-nFE^0_{cell} [/tex]
   
   Of course, now this translates to another convention : that a negative free energy change tells you that the reaction is plausible. To make this more intuitive, it may help to go a step further.
   
   [tex]\Delta G^0 = -RT lnK [/tex]
   [tex]\Delta G^0 < 0 \implies lnK > 0 \implies K > 1 [/tex]

    

   Gokul43201, May 6, 2006

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in