Electromagnetic Induction and rectangular loop

AI Thread Summary
The discussion revolves around the analysis of a rectangular loop and a slide wire in a uniform magnetic field. The force exerted on the wire while moving at speed v is expressed as B^2 L^2 v/R. For part b, the user initially attempts to calculate the distance the wire moves before coming to rest by assuming constant acceleration, which is incorrect due to the force being velocity-dependent. Instead, the correct approach involves using the relationship F = ma and integrating the variables to find the distance. The conversation emphasizes the importance of recognizing that the force diminishes as the wire slows down.
adrian116
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the question is that:
A rectangular loop with width L and a slide wire with mass m are as shown in Fig. A uniform magnetic field \vec B is directed perpendicular to the plane of the loop into the plane of the figure. The slide wire is given an initial speed of v_0 and then released. There is no friction between the slide wire and the loop, and the resistance of the loop is negligiblein comparison to the resistance R of the slide wire. a) Obtain an expression for F, the magnitude of the force exerted on the wire while it is moving at speed v. b). Show that the distance x that the wire moves before coming to rest is \frac{m v_0 R}{a^2 B^2}

i have done part a ,
the ans. is \frac{B^2 L^2 v}{R}
but for part b ,
i can just calculate half of the value of x mentioned in the question.
i did it in this way

subt. F from a to F=ma to find the acceleration
then subt. the ans. to
v^2=u^2+2as by taking v=0 and u=v.
is there any mistake?
 

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adrian116 said:
the question is that:
A rectangular loop with width L and a slide wire with mass m are as shown in Fig. A uniform magnetic field \vec B is directed perpendicular to the plane of the loop into the plane of the figure. The slide wire is given an initial speed of v_0 and then released. There is no friction between the slide wire and the loop, and the resistance of the loop is negligiblein comparison to the resistance R of the slide wire. a) Obtain an expression for F, the magnitude of the force exerted on the wire while it is moving at speed v. b). Show that the distance x that the wire moves before coming to rest is \frac{m v_0 R}{a^2 B^2}

i have done part a ,
the ans. is \frac{B^2 L^2 v}{R}
but for part b ,
i can just calculate half of the value of x mentioned in the question.
i did it in this way

subt. F from a to F=ma to find the acceleration
then subt. the ans. to
v^2=u^2+2as by taking v=0 and u=v.
is there any mistake?
You have a force that is proportional to the velocity. As the wire slows, the force diminishes. You cannot use the initial acceleration as a constant.
 
then , what should i do , can u give me some hints?
 
adrian116 said:
then , what should i do , can u give me some hints?
F = ma = mdv/dt = m(dv/dx)(dx/dt) = mvdv/dx

You can separate variables and integrate.
 
thx so much~
 
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