Electromagnetic Induction and rectangular loop

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 22K views
adrian116
Messages
43
Reaction score
0
the question is that:
A rectangular loop with width L and a slide wire with mass m are as shown in Fig. A uniform magnetic field [itex]\vec B[/itex] is directed perpendicular to the plane of the loop into the plane of the figure. The slide wire is given an initial speed of [itex]v_0[/itex] and then released. There is no friction between the slide wire and the loop, and the resistance of the loop is negligiblein comparison to the resistance R of the slide wire. a) Obtain an expression for F, the magnitude of the force exerted on the wire while it is moving at speed v. b). Show that the distance x that the wire moves before coming to rest is [itex]\frac{m v_0 R}{a^2 B^2}[/itex]

i have done part a ,
the ans. is [itex]\frac{B^2 L^2 v}{R}[/itex]
but for part b ,
i can just calculate half of the value of x mentioned in the question.
i did it in this way

subt. F from a to [itex]F=ma[/itex] to find the acceleration
then subt. the ans. to
[itex]v^2=u^2+2as[/itex] by taking v=0 and u=v.
is there any mistake?
 

Attachments

  • Picture0005.jpg
    Picture0005.jpg
    37.8 KB · Views: 2,044
Last edited:
Physics news on Phys.org
adrian116 said:
the question is that:
A rectangular loop with width L and a slide wire with mass m are as shown in Fig. A uniform magnetic field [itex]\vec B[/itex] is directed perpendicular to the plane of the loop into the plane of the figure. The slide wire is given an initial speed of [itex]v_0[/itex] and then released. There is no friction between the slide wire and the loop, and the resistance of the loop is negligiblein comparison to the resistance R of the slide wire. a) Obtain an expression for F, the magnitude of the force exerted on the wire while it is moving at speed v. b). Show that the distance x that the wire moves before coming to rest is [itex]\frac{m v_0 R}{a^2 B^2}[/itex]

i have done part a ,
the ans. is [itex]\frac{B^2 L^2 v}{R}[/itex]
but for part b ,
i can just calculate half of the value of x mentioned in the question.
i did it in this way

subt. F from a to [itex]F=ma[/itex] to find the acceleration
then subt. the ans. to
[itex]v^2=u^2+2as[/itex] by taking v=0 and u=v.
is there any mistake?
You have a force that is proportional to the velocity. As the wire slows, the force diminishes. You cannot use the initial acceleration as a constant.
 
then , what should i do , can u give me some hints?