1. The problem statement, all variables and given/known data https://lh3.googleusercontent.com/HPLcLqiEmZPOh_7gIM0jNK4cXk6KMgMz2StpKfDC4QDa5Z66Cc-CQ4HKx8nY1n8AF74paz2NM3aaqmVPDVUxAkY9nGhaZGP6f9nu4ItV1cB6GFRASPnt1GI3tmWoOz47r5163k5mJf89FAwKHOkW6XCIeD1pYHAr1J2UXQCPlA1L3njmFTIZOYQYjXpmwO-FQ7WQ3ntnb6kUUpmoxk8UHqYDvxIP04tFgdP6Z654-yOCf-KJaqzbWkv6L4to4kR2BaMA017mxG9ZTVofrA_vuIVVlWV7-9QpguWva93N4GYGItiXDB59hPJpUjVLE6LNKwS04Imvzj1x8NWIswca14eg5KmWe4riQeVybL5sb5xhQ2Q5OZbqMgrS1k-KMtQjoOomr3YkCSEmVWrJSW7ltaW71et85585uwz7VUzGX-mvlro2VklAN349QPfCqqOBr3UUTHOEdaizmutciSU7RH9OMdsyCVEuBuT28icPDkmeC5rDRjnwEaUMbCX5ntOSCL9hrPkhEEpMY7nF1vee4vNoPIfZjVRa4UP5l7kGj_RNIcqlTqdORWIscWpCFypHTRZRurdZ8b_MLPr2lVZBY0TLEC4MK_kC7oIgE_C41_phTjGW3dQC=w757-h450-no [Broken] 2. Relevant equations F = QvB V = kQ/r 3. The attempt at a solution I'm just learning this stuff and I wasn't given an example of any kind so I don't really know how to start this question... For 8.a) If I'm using the RHR and my thumb is facing in the x direction then I believe the proton will be deflected downwards? I was also under the impression that work done had to be parallel to the force and if the proton is being deflected then there is no work done? 8.b) I tried doing mv/r = qB and rearranging the formula for r = mv/qB but if I don't have velocity and I'm left with 2 variables I'm at a loss. Any help would be greatly appreciated.