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1. Consider the fields:
\vec{E} = E0 * cos(kx-wt)\vec{e}1
\vec{B} = B0 * cos(kx-wt)\vec{e}1
Do these fields solve the maxwell equations? if so, what do they describe?
2. Homework Equations
\vec{E} = E0 * cos(kx-wt)\vec{e}1
\vec{B} = B0 * cos(kx-wt)\vec{e}1
if these functions holds for the maxwell equations then,
\nabla.\vec{B}=0
\nabla.\vec{E}=0
that is
\nabla.\vec{B}=-\vec{B}0.\vec{K}*Sin(kx-wt)
this equation is equal to zero only if and only if B0.K = 0 that means, they are perpendicular vectors. that is the constraint.
I guess the \vec{e} means that the wave propagates only in the x direction? since e1=<1,0,0>
hum, I really can't tell if that's the appropriate answer, so could you help please ?
thanks in advance
so the question what do they describe, I wrote the propagation of the electromagnetic wave in the x-direction as time increases.
\vec{E} = E0 * cos(kx-wt)\vec{e}1
\vec{B} = B0 * cos(kx-wt)\vec{e}1
Do these fields solve the maxwell equations? if so, what do they describe?
2. Homework Equations
\vec{E} = E0 * cos(kx-wt)\vec{e}1
\vec{B} = B0 * cos(kx-wt)\vec{e}1
The Attempt at a Solution
if these functions holds for the maxwell equations then,
\nabla.\vec{B}=0
\nabla.\vec{E}=0
that is
\nabla.\vec{B}=-\vec{B}0.\vec{K}*Sin(kx-wt)
this equation is equal to zero only if and only if B0.K = 0 that means, they are perpendicular vectors. that is the constraint.
I guess the \vec{e} means that the wave propagates only in the x direction? since e1=<1,0,0>
hum, I really can't tell if that's the appropriate answer, so could you help please ?
thanks in advance
so the question what do they describe, I wrote the propagation of the electromagnetic wave in the x-direction as time increases.