Electromagnetics = Biot-Savart Law around square path

AI Thread Summary
To find the B-field at the center of a square loop with width w and current I, the Biot-Savart Law is applied. The equation provided is B = [(μo*I*aФ)/(4∏*ρ)](cosα2 – cosα1), but there is confusion regarding the angles α1 and α2. The user attempted to use (w/2) for the radial component ρ and assigned 45 degrees to α2 and 90 degrees to α1, which is incorrect. Clarification is sought on the proper angles to use for accurate calculations, as well as the definitions of ρ, α1, and α2 in relation to the derived equation. Understanding these components is essential for solving the problem correctly.
satchmo05
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Homework Statement


Find the B-field at the center of the square loop located above the xy plane, with width (w), and current I rotating counter-clockwise.


Homework Equations


Here is the given equation:
B = [(μo*I*aФ)/(4∏*ρ)](cosα2 – cosα1)

The final answer is for the B-field about the loop is:
B = [(4μo*I)/(∏*w*(√2))]az
How do I obtain this answer? I am having trouble with the angles that I am supposed to use.

The Attempt at a Solution


I used (w/2) for the radial component, ρ. I used 45 degrees for α2, and 90 degrees for cosα1, and this is obviously wrong. Which angles do I use to get the correct angle?
 
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