Electromagnetics: Electric Field from Conductor?

  • Thread starter Thread starter Amith2006
  • Start date Start date
  • Tags Tags
    Electro Magnetics
Amith2006
Messages
416
Reaction score
2
Sir,
When a current is passed through a conductor, a magnetic field is produced around it. Due to the flowing charges, is an electric field also produced around the conductor?
 
Physics news on Phys.org
You might have to think just about when, how and where is and electric field is formed. Has magnetic effect of current flowing through a conductor anf those forces started for you. Then you must understand the following. Probably you read H C Verma or Resnick Halliday for better understanding. You can even refer to the NTSC CBSE 11-12th textbooks. The explanation is in simple english there.
 
yes there is also an electric field. that's why power lines humm because of the huge potential they have relative to the air and the effect it has on the moisture
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top