Electron accelerated through a potential difference

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SUMMARY

The discussion centers on calculating the velocity of an electron accelerated through a potential difference of 1x106 V. The initial approach used the classical kinetic energy formula K=(1/2)mv2, leading to an incorrect result of v=1.98c, which exceeds the speed of light. Participants clarified that this scenario is relativistic, necessitating the use of relativistic kinetic energy equations to accurately determine the electron's momentum and velocity.

PREREQUISITES
  • Understanding of relativistic physics concepts
  • Familiarity with kinetic energy equations
  • Knowledge of electron properties, specifically mass and charge
  • Basic grasp of potential difference and its effects on charged particles
NEXT STEPS
  • Study the relativistic kinetic energy formula: K = γmc2 - mc2
  • Learn about the Lorentz factor (γ) and its application in relativistic calculations
  • Explore the concept of relativistic momentum: p = γmv
  • Investigate the implications of potential difference on particle acceleration in high-energy physics
USEFUL FOR

This discussion is beneficial for physics students, educators, and professionals involved in high-energy particle physics, particularly those focusing on electron dynamics and relativistic effects.

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Homework Statement


I am trying to get the velocity of an electron which has been accelerated through a potential difference of 1x106 V, so that i can find its momentum.

Homework Equations


K=(1/2)mv2
v=sqrt(2K/m)

The Attempt at a Solution


So , K = 1x106eV and m = 0.511x106eV/c2

v=sqrt(2x1x106/.511x106eV/c2)

then the c2 comes out and I am left with

v=sqrt(2x1x106[/SUPeV]/.511x106eV)c

v=1.98c

which is clearly wrong since v can't be higher than the speed of light,
what am i overlooking?
 
Physics news on Phys.org
An electron passing through a 1x10^6 V potential is a highly relativistic situation. The kinetic energy you wrote down is no longer true.
 
So, how do i find K, or the momentum for that matter?
 

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