DrDu said:
I would be really interested about the opinion of some mathematician like A.Neumaier, who recently joined this forum, on that discussion so I thought I bring it up on the agenda once more.
OK, I read the whole thread, and comment below
(i) on some of the posts of Tom Stoer, where I disagree or have questions,
(ii) on mathman's original posting.
Note that the fact I don't comment the others does not mean that I agree with what they wrote.
As we discussed in the other thread, Tom Stoer's derivation of the neutrality of the universe implicitly assumes boundary conditions at infinity that smuggle in the desired conclusion as an assumption.
tom.stoer said:
DrDu said:
This whole operator G becomes ill-defined on a torus for Q ne 0.
...
so \mathbf{E}=-i \mathbf{K} \rho(\mathbf{K})/K^2+\mathbf{E}_\perp
I think this is not true. E lives the bosonic sector of the Hilbert space whereas the charge density lives in the fermionic sector. That means you can't solve the equation as an operator equation.
This would be the case in a free theory. But in the interacting theory, all fields act (densely, after smearing) on the whole Hilbert space of the interacting representation. Thus solving equations makes at least formally sense, as long as noncommutativity is respected. Thus your criticism does not hold water.
tom.stoer said:
The [temporal] gauge isn't unsuitable. It's püerfectlywell defined and in the context of canonical quantization it's the gauge that makes most sense! The problem is that most people are not familiar with it as standard QFT textbooks do only talk about Lorentz gauge.
One can find it in the QFT book by Bjorken and Drell (Vol. 2).
tom.stoer said:
Now the requirement is to have gauge-invariant physical states, i.e. every physical state is a color-singulet! But this automatically means that all Q's have zero eigenvalue on physical states! Please note that this shortcut is not possible in QED as the gauge group has an abelian structure which does not immediately single out color singulets.
The quantum numbers (masses, charges, and flavors) of a particle are a property of its single particle representation, not of a particular state. Charge-neutrality means transforming to the trivial representation, while nontrivial charge says transforming according to a nontrivial representation. Thus it is not a question about eigenvectors. Physical states need not transform trivially; gauge invariance only requires that the states psi and U psi describe the same physical situation when U is a local gauge transformation. (Otherwise we wouldn't even have photons...)
tom.stoer said:
The standard model requires that certain charges of different types of leptons and quarks add up to zero b/c of anomaly cancellation. w/o this perfect match the theory would have triangle anomalies in the chiral el.-weak sector which would spoil its mathematical consistency.
For the sake of definiteness, could you please write down this constraint explicitly?
mathman said:
The charge of an electron is exactly equal in magnitude to that of a proton (2 up quarks plus down quark). What is the theoretical basis for this, or is essentially a fact of nature that is accepted?
Phenomenologically, electrons and many ions are stable in isolation (i.e., with nothing else in the universe), so these are observable charged states of QED (when enhanced with nuclei in case of ions).
Also, we observe on a daily basis that the bigger a metal object the more charge it can hold without being unstable and discharge. Thus a universe with small but nonzero net charge is consistent with experiment (and presumably therefore also with the standard model). If the charge imbalance is too large, particles of the excess charge would move away from each other until their fields will hardly be noticable to each other. This is also consistent with QFT, due to the cluster decomposition property of particles and bound states (discussed, e.g., in Weinberg's Vol. I). Thus locally, one expects to see a rough but not exact charge balance. Which is what we actually observe.