Electron potential/momentum problem

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The discussion centers on calculating the potential difference required to accelerate electrons that produce x-ray radiation with a wavelength of 1.24 angstroms. Participants highlight the need to use the correct equations, specifically the relationship between photon energy and wavelength, and emphasize that the momentum equation used was incorrectly applied to the photon instead of the electron. The correct approach involves starting with the energy of the x-ray photon to determine the necessary kinetic energy of the electrons. Clarification is sought on the appropriate formulas to use, particularly those relating to photon energy and electron momentum. Understanding these concepts is crucial for solving the problem accurately.
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Homework Statement


To produce x-ray radiation, electrons are accelerated in vacuum and aimed so as to collide with a target. Assume that all of the electron kinetic energy is converted into the energy of the x-ray photon on collision and that the wavelength of the resulting radiation is 1.24 angstroms.

Homework Equations


h^2/(2*(e)(m)(λ)^2)

The Attempt at a Solution


(6.63*10^-34)^2/(2(1.6*10^-19)(9.11*10^-31)(1.24*10^-9)^2)

=.979 V
/1000 for kV = .000979 kV. I entered this answer and it told me it was incorrect.
 
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That equation is unknown to me. Try starting out with the basic equation for the energy of the x-ray photon.
 
orangeincup said:

Homework Statement


To produce x-ray radiation, electrons are accelerated in vacuum and aimed so as to collide with a target. Assume that all of the electron kinetic energy is converted into the energy of the x-ray photon on collision and that the wavelength of the resulting radiation is 1.24 angstroms.

Homework Equations


h^2/(2*(e)(m)(λ)^2)

The Attempt at a Solution


(6.63*10^-34)^2/(2(1.6*10^-19)(9.11*10^-31)(1.24*10^-9)^2)

=.979 V
/1000 for kV = .000979 kV. I entered this answer and it told me it was incorrect.

What is the question?
You did not write any equation. What does the formula in 2 mean?
 
The question is "What potential difference must the electron be accelerated? (answer in kV) "
Enter the electron momentum in kg*m/s

My equation I found using KE=1/2mv^2, λ = h / p, and I guess I messed something up

so I have the λ=1.26, the mass of an electron, the fact it is a vaccum, the charge of an electron, planks constant. What kind of formula should I be using?

h/ λ =p
(6.63*10^-34)/(1.24*10^-10) = 5.34*10^-24 (momentum?)
 
orangeincup said:
The question is "What potential difference must the electron be accelerated? (answer in kV) "
Enter the electron momentum in kg*m/s

My equation I found using KE=1/2mv^2, λ = h / p, and I guess I messed something up

so I have the λ=1.26, the mass of an electron, the fact it is a vaccum, the charge of an electron, planks constant. What kind of formula should I be using?
You need a formula that contains the accelerating voltage.
orangeincup said:
h/ λ =p
(6.63*10^-34)/(1.24*10^-10) = 5.34*10^-24 (momentum?)
The problem asks the momentum of the electron. h/ λ =p is right if you use the wavelength of the electron, but you substituted the wavelength of the photon, so you got the momentum of the photon.
 
The kinetic energy of the electrons are used to produce the x-ray photons. So I suggest starting out with the energy of the x-ray photons. Do you know what the equation is for the energy of a photon (according to Planck and as used by Einstein to explain the photoelectric effect)?
 
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