Electron-Proton Relative Speed: Solving for 0.9c and -0.0994c

AI Thread Summary
The discussion revolves around calculating the relative speed of an electron moving left at 0.9c and a proton moving right at 0.9c. The correct formula for combining relativistic velocities is provided, which is s = (v + u) / (1 + (vu/c²)). A participant initially miscalculated the speed as 0.18c but later corrected it to approximately -0.994c after receiving guidance. The importance of consistent units in the calculations is emphasized, clarifying the misunderstanding. The conversation highlights the complexities of relativistic physics and the need for careful application of formulas.
najisalem2009
Messages
13
Reaction score
0

Homework Statement


A laboratory experiment shoots an electron to the left at 0.9c. What is the electrons speed relative to a proton that is moving to the right at 0.9c?

I have no idea how to attempt this problem i know the answer is -.0994c but I am not sure how to get this answer?
 
Physics news on Phys.org
anyone?
 
Welcome to Physics Forums.

If you were assigned a question like this, then you would have been given the equation for combining relativistic velocities. It should be in your textbook or class lecture notes -- it's a pretty standard equation.
 
So i found the equation Its s= (v+u)/1+(vu/c²)

s=(0.9c+0.9c)/1+(0.9c)(0.9c)/(2.98*10⁸)²
i get s=.18c but the answer is -0.994c
 
Question: Why did you leave "0.9c" as it was, but then expressed "c" later as 2.98*10^8 m/s?

(This is where your problem resides.)
 
najisalem2009 said:
So i found the equation Its s= (v+u)/1+(vu/c²)

s=(0.9c+0.9c)/1+(0.9c)(0.9c)/(2.98*10⁸)²
i get s=.18c
It's wrong. That must be s=(0.9c+0.9c)/(1+0.81)=1.8c/1.81=0.994c
 
oh ok thanks a lot guys for clearing that up for me
 
Back
Top