Electron Speed in a Voltage Gradient

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SUMMARY

The discussion centers on calculating the speed of an electron in a 15kV voltage gradient. The relevant equation used is U=q*V, where U represents potential energy, q is the charge of the electron, and V is the voltage. Participants confirm that since the initial kinetic energy is zero and the final potential energy is also zero, the final kinetic energy (Kf) can be substituted for U. This allows for the determination of the electron's speed just before it hits the cathode.

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Homework Statement



The voltage between two plates is 15kV. If an electron's speed is zero as it leaves the anode, what is its speed just before it hits the cathode?

Homework Equations



U=q*V



The Attempt at a Solution



I guess my question is can I use the equation Ui + Ki = Uf + Kf and since there is no initial kinetic anergy and no final potential energy can I substitute Kf of the electron in for the U in the equation U=q*V? Would q be the charge of the electron?
 
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Yes you can do what you suggested, Kf=q*V and you can find the speed from Kf. And yes q is the charge of the electron.

Hope it helps,
 
yes thanks
 

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