The photocurrent of a photocell is cut off by a retarding potential of 2.92V for radiation of wavelength 250nm. What is the work function of the photoemitter?(adsbygoogle = window.adsbygoogle || []).push({});

I want to use the equation: PHI=hc/lambda-Ve, where V is the stopping voltage (sorrry I don't know how to do the Greek letters for PHI and lambda).

My question: is Ve just 2.92 or is V 2.92 and e 1.602*10^-19? I have tried both ways, adjusting h as required, and I get two different answers. Using Ve=2.92 gives a answer that makes more sense, but I don't quite understand why V=2.92 is not just V. Any advice? Thanks

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# Homework Help: Electron volts

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