Electrostatic Field: Work Done by Electric Forces

AI Thread Summary
The discussion focuses on calculating the work done by electric forces when moving a charge of 1 nC from the origin to the point (1m, 1m, 1m) in a specified electrostatic field. Participants clarify the expression for the electric field E and emphasize the need to calculate the net force acting on the charge to determine the work done. Confusion arises over the notation used for the electric field, particularly regarding the unit vectors and the correct representation of E as a function of coordinates. The urgency of the assignment deadline adds pressure to find a solution quickly. Overall, the conversation highlights the importance of understanding the definitions and calculations involved in electrostatics.
musabkheiry
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what is the work done by electric forces in moving a charge Q=1 nC from the origin to the point (1m, 1m, 1m) in the electrostatic field given by E=(x,y,z) = (x* (a sub x) + y^2*(a sub y) - (a sub z) V/m in the Cartesian coordinate system along the straight line joining two points?
 
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hi musabkheiry! welcome to pf! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Hi tiny-tim

In fact i have to submit my assignment after 6 hours from now ...
i tried to solve it .. and i don't know how to start to solve the question :( ... i don't want to get zero :( ... could you please help me
 
you must know something :confused:

what is the definition of work done ?

how would you apply it in a simple case?

what is it about this case that stops you?​

(btw, do you mean E = (x, y2, 1) V/m ?)
 
i guess first i need to calculate the net force for the whole system and then i can find the work done ,,, what is confuse me is .. E=(x^x+y^2y+z)
 
musabkheiry said:
what is confuse me is .. E=(x^x+y^2y+z)

let's see, you wrote …
musabkheiry said:
E=(x,y,z) = (x* (a sub x) + y^2*(a sub y) - (a sub z) V/m

i found that rather confusing, and i guessed that ax ay and az were meant to be the unit vectors in the x y and z directions

(and that "E=(x,y,z)" should have been "E(x,y,z)", ie the vector E as a function of x y and z: E = (Ex, Ey, Ez) = Exax + Eyay + Ezaz )
 
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