Electrostatic force including coulombs law

In summary, the problem involves transferring a portion of charge from one tiny sphere to another nearby one. The electrostatic force between the spheres is given by the equation F=k(Q-q)q/r^2, and the goal is to find the value of q/Q that will result in the force being at 1/2 of its maximum possible value. The attempt at a solution involves differentiation and setting the equation equal to 1/2, with Q and r being constants set to 1.
  • #1
th3plan
93
0

Homework Statement



Of the charge Q initially on a tiny sphere, a portion q is to be transferred to a second, nearby sphere. Both spheres can be treated a particles. For what value of q/Q>0.5 will the electrostatic force between the two parts have 1/2 of the maximum possible value?



The Attempt at a Solution



ok i drew a picture and i know that sphere 1 is Q-q , and sphere 2 is q, and i plug into equation

F=k(Q-q)q/r^2

i differentiate and get qQ-2q now what i do from here, to get 1/2 maximum possible value

i know to get maximum i set equal to zero, do i set this equal to 1/2? How would i solve it for q/Q ratio if its equal to 1/2?
 
Physics news on Phys.org
  • #2
Q is a constant. just set it equal to 1. same with r.
 
  • #3


I would like to offer some clarification on the content being discussed. The electrostatic force, as described by Coulomb's law, is a fundamental force that exists between electrically charged particles. It is responsible for many phenomena in our everyday lives, such as the attraction and repulsion between objects, the functioning of electronic devices, and the behavior of atoms and molecules.

In this homework problem, we are dealing with the transfer of charge between two tiny spheres. The electrostatic force between these spheres can be calculated using Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Now, to determine the value of q/Q that will result in the electrostatic force being half of its maximum possible value, we can set up the following equation:

F = k(Q-q)q/r^2 = 1/2 * kQ^2/r^2

This equation represents the electrostatic force at half its maximum value, where k is the Coulomb's constant and r is the distance between the spheres. To solve for q/Q, we can rearrange the equation and get:

q/Q = (2r^2 - 1)/(2r^2)

Therefore, for q/Q to be greater than 0.5, the value of r must be greater than 1/sqrt(2) or approximately 0.707. This means that the distance between the spheres must be less than 1.414 times the radius of each sphere.

In conclusion, Coulomb's law allows us to calculate the electrostatic force between charged particles, and by setting the force equal to half of its maximum value, we can determine the ratio of charge transfer needed for that force to occur. This can be useful in understanding and predicting the behavior of charged particles in various situations.
 

What is electrostatic force?

Electrostatic force, also known as Coulomb's law, is the force that exists between two electrically charged particles. It is a fundamental force in nature and is responsible for the attraction and repulsion of charged particles.

How is electrostatic force calculated?

Electrostatic force is calculated using Coulomb's law, which states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for calculating electrostatic force is F = k(q1q2)/r^2, where F is the force, k is the Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

What is the unit of electrostatic force?

The unit of electrostatic force is Newtons (N), which is the unit of force in the International System of Units (SI). This unit is derived from the formula for electrostatic force, F = ma, where F is the force, m is the mass, and a is the acceleration. In the case of electrostatic force, the acceleration is due to the attraction or repulsion of charged particles.

How does distance affect electrostatic force?

According to Coulomb's law, the force between two charged particles is inversely proportional to the square of the distance between them. This means that as the distance between the particles increases, the force decreases. This relationship is known as the inverse-square law.

What is the difference between electrostatic force and gravitational force?

Electrostatic force and gravitational force are both fundamental forces in nature, but they have some key differences. Electrostatic force is the force between charged particles, while gravitational force is the force of attraction between any two objects with mass. Additionally, electrostatic force can be either attractive or repulsive, depending on the charges of the particles, while gravitational force is always attractive.

Similar threads

  • Introductory Physics Homework Help
Replies
17
Views
401
  • Introductory Physics Homework Help
Replies
12
Views
544
  • Introductory Physics Homework Help
Replies
21
Views
667
Replies
22
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
153
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
10
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
896
  • Introductory Physics Homework Help
Replies
11
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
832
Back
Top