Electrostatic Potential for Two Concentric Cylindrical Shells

AI Thread Summary
The discussion centers on calculating the electrostatic potential V(r) for two concentric cylindrical shells with different charge densities. The potential is derived using Gauss's law, leading to expressions for V(r) in different regions: inside the inner shell, between the shells, and outside the outer shell. The potential difference ΔV between the inner and outer shells is calculated, and the kinetic energy of a positive charge released from the inner shell is determined based on the potential difference. Participants emphasize the need to correctly apply the equations for cylindrical geometries and clarify the behavior of the electric field in various regions. Understanding these concepts is crucial for solving the problem accurately.
sweetdion
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Homework Statement


Two very long hollow conducting cylindrical shells are situated along the x-axis. The shells are concentric and have negligible thickness. The inner shell has a radius a and a linear charge density +lambda, while the outer shell has a radius b and a linear charge density -lambda. Take the zero of electrostatic potential to be at r = 0. The coordinate r measures the distance from the common axis of the two cylinders in a region far from either end.

a) Determine the electrostatic potential V(r) for all values of r
b) Sketch V(r) vs. r for all r
c) Determine the potential difference DeltaV between r=a and r=b
d) If a positive charge +q is released from rest at r=a, what will be its kinetic energy when it reaches the outer cylinder at r=b.


Homework Equations


V(r)=q/4piE0r
Delta V=Vb-Va=q/4PiE0*(1/rb-1/ra)
Ke=1/2mv^2
U=kq1q2/r
KEf=Ui


The Attempt at a Solution


a) at r=a
V=q/4piE0a

at r=b
V=q/4piE0b

b) as the radius increases the potential goes down. It starts at some positive y value and ends at some negative y value.

c)Delta V=Vb-Va=q/4PiE0*(1/b-1/a)

d) U=kq1q2/a
1/2mv^2=kq1q2/r
v^2=2kq1q2/mr
v=(2kq1q2/mr)^1/2
 
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I'm just wanting to know if i got this right
 
sweetdion said:

Homework Statement


Two very long hollow conducting cylindrical shells are situated along the x-axis. The shells are concentric and have negligible thickness. The inner shell has a radius a and a linear charge density +lambda, while the outer shell has a radius b and a linear charge density -lambda. Take the zero of electrostatic potential to be at r = 0. The coordinate r measures the distance from the common axis of the two cylinders in a region far from either end.

Homework Equations


V(r)=q/4piE0r

The formula you quoted refers to a point charge. These are very long cylinders.

ehild
 
V(r)= 1/4piE0 Int dq/r
 
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Part C)

EA=Qenc/E0
E=lamda/PirE0
Delta V=-lamda/PiE0 Int dr/r
Delta V= lamda/PiE0 ln(b/a)
 
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You have started part C well, but it is still wrong.

The first questions were:

"a) Determine the electrostatic potential V(r) for all values of r
b) Sketch V(r) vs. r for all r"

So what is the potential for r<a? for r>b?

ehild
 
what equation am i supposed to use to figure out the potential? so confused.

V (r) = 1/4PiE0 * Int dq/r ?
 
Find the electric field first. What is it inside the inner cylinder? Between a and b? for r>b? Use Gauss' law.
For r<0, the enclosed charge is 0. If a<r<b, the enclosed charge is +lambda *Length of the cylinder. For a cylinder with r>b, the enclosed charge is 0. E is the negative gradient of the potential. What is the potential like if E=0?

ehild
 
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