Electrostatics -Electric Field and Potential

AI Thread Summary
The discussion revolves around calculating the absolute potential at the center of a 30 cm diameter metal sphere given an electric field strength of 3 MV/m at its surface. The initial calculations incorrectly used the diameter instead of the radius, leading to an incorrect potential value. The correct approach involves using the radius of 0.15 m in the formula for potential, V = kQ/r. After correcting the radius, the potential can be accurately determined. The conversation highlights the importance of using the correct measurements in electrostatics calculations.
abelthayil
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Homework Statement



A 30 cm diameter metal sphere hangs from a thread in the middle of a very large room. So its surroundings are essentially at infinity. If the electric field at tis surface is equal to the break down strength of air 3MV/m, what is the absolute potential at the center of the sphere?
A) 450 kV
B) 150 kV
C) 300 kV
D) 0

The answer is from what I've searched online is A


2. The attempt at a solution


The Electric FIeld at the surface is 3,000,000 V/m so kQ/r2=3,000,000
The only unknown is charge and solving we get Q=3*106*r2/k
where (k=1/4pi epsilon nought)

so potential at the centre =kQ/r=9* 105 V which is wrong so help please..
 
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Your method is correct, V=kQ/r, so E=kQ/r^2, V=Er...but you have to use r=0.15 m, instead of 0.3m. It is the radius.

ehild
 
Oh YES ! How silly of me Thanks !
 
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