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Electrostatics uniform electric field of magnitude

  1. May 7, 2014 #1
    An electron with speed 2.00×10^7m/s is traveling parallel to a uniform electric field of magnitude 1.16×10^4N/C .

    #1). How far will the electron travel before it stops?
    f=ma=Eq=-eE
    a=-eE/m
    I got a=-2.81x10^15
    Then I used v(f)^2=v(i)^2+2a(x-x(i))
    Solved for x.....
    x=-(V(i))^2/2(a)
    x=.0712m

    #2). How much time will elapse before it returns to its starting point?
    v=v(i) +at
    If we want the time BEFORE it returns
    t=2V(i)/a
    t=1.42x10^-8 s

    I got both wrong on Mastering Physics ...... Please help I don't know what I am doing wrong
     
  2. jcsd
  3. May 7, 2014 #2

    haruspex

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    You appear to have used a field of 1.6E4 instead of 1.16E4.
     
  4. May 7, 2014 #3
    !!!!!
    I got threw off with all the sixes! Thanx a bunch!
     
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