Elevator and spring problem

In summary, the problem involves an elevator weighing 754 kg that breaks when it is 20.8 m above a huge spring with a spring constant of 6.93x10^4 N/m. The goal is to calculate the amount the spring compresses, taking into account both the work done by the spring and gravity. Using conservation of energy, the equation (1/2)mV^2-(1/2)mVinitial^2= -(1/2)kx^2 + mgx is used to solve for x, the distance the spring is compressed. However, this equation may result in an incorrect answer and the solution may require the use of the quadratic equation.
  • #1
whereisccguys
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Problem: An elevator cable breaks when a 754 kg elevator is 20.8 m above the top of a huge spring (k = 6.93×104 N/m) at the bottom of the shaft. Calculate the amount the spring compresses (note that here work is done by both the spring and gravity).

i calculated the speed of the elevator just before it hits the spring which is
Vinitial = 20.19 m/s

the equation i used was (1/2)mV^2-(1/2)mVinitial^2= -(1/2)kx^2 + mgx
x is the distance the spring was compressed
and at distance x the current velocity = 0 because it is not moving at all anymore
therefore the equation becomes -(1/2)mVinitial^2= -(1/2)kx^2 + mgx
i plugged in all the numbers and solved by the quadratic equation.. but still came up with the wrong answer...
can someone help?
 
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  • #2
use conservation of energy... before the cable breaks, the elevator is steady, with a potential energy mgh... after the elevator hit the spring and compressed it, the velocity is also zero, potential energy become 1/2kx^2

mgh=1/2kx^2
x=sqrt(2mgh/k)
 
  • #3


It seems like you have the right approach to solving this problem, but there may be an error in your calculations or in the numbers you plugged in. Here are a few things to double check:

1. Make sure you are using the correct units for all the values. For example, the mass should be in kilograms and the spring constant should be in Newtons per meter.

2. Check your signs carefully. Since the elevator is initially moving downwards, the initial velocity should be negative and the final velocity should be zero. The work done by gravity and the spring should also have opposite signs.

3. Make sure you are using the correct formula for the work done by the spring. It should be (1/2)kx^2, not (1/2)kx.

4. Double check your calculations or try using a different method to solve the problem. Sometimes a small mistake can lead to a significantly different answer.

If you are still having trouble, it may be helpful to ask a classmate or your instructor for assistance. They may be able to identify where you went wrong or provide additional guidance on how to solve the problem.
 

1. What is the elevator and spring problem?

The elevator and spring problem is a classic physics problem that involves a mass attached to a spring inside an elevator. The elevator can either be at rest or moving with a constant velocity. The goal is to determine the behavior of the mass-spring system in each scenario.

2. How do you solve the elevator and spring problem?

The first step in solving the elevator and spring problem is to draw a free body diagram of the mass and identify all the forces acting on it. Then, using Newton's second law, the equation of motion for the mass can be derived and solved to determine the displacement, velocity, and acceleration of the mass.

3. What are the key assumptions made in solving the elevator and spring problem?

The main assumptions made in solving the elevator and spring problem are that the elevator is a frictionless environment and that the spring obeys Hooke's law. This means that the spring force is directly proportional to the displacement of the mass from its equilibrium position.

4. How does the behavior of the mass-spring system differ between a stationary and moving elevator?

In a stationary elevator, the mass-spring system will oscillate with a constant amplitude and frequency. In a moving elevator, the spring will experience an additional force due to the elevator's acceleration, causing the system to behave differently depending on the direction of the elevator's motion.

5. What real-life applications does the elevator and spring problem have?

The elevator and spring problem is commonly used to analyze the behavior of shock absorbers in cars, as well as the motion of a person on a spring-loaded diving board. It also has applications in understanding the behavior of buildings during earthquakes and in designing suspension systems for vehicles.

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