(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

At the bottom of this page:

http://www.cv.nrao.edu/course/astr534/LorentzTransform.html

It states;

Lorentz factor:

* y =gamma x=y(x'+vt') and x'=y(x−vt)

Eliminating x from this pair of equations yields

t=y(t'+vx'/c^2)

How did they eliminate x?

3. The attempt at a solution

I'm taking the x value which is y(x'+vt') and substituting this into the x value in the x' equation.

So I'm getting;

x' = y^2(x'+vt')-yvt

Then I've separated the equation so that t is on LHS;

t = [y^2(x' + vt')] / yv

If anyone knows how this is done, I'd be very interested in learning! Thank you.

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# Eliminating x in Lorentz Transformation

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