- #1
ZedCar
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Homework Statement
At the bottom of this page:
http://www.cv.nrao.edu/course/astr534/LorentzTransform.html
It states;
Lorentz factor:
* y =gammax=y(x'+vt') and x'=y(x−vt)
Eliminating x from this pair of equations yields
t=y(t'+vx'/c^2)
How did they eliminate x?
The Attempt at a Solution
I'm taking the x value which is y(x'+vt') and substituting this into the x value in the x' equation.
So I'm getting;
x' = y^2(x'+vt')-yvt
Then I've separated the equation so that t is on LHS;
t = [y^2(x' + vt')] / yv
If anyone knows how this is done, I'd be very interested in learning! Thank you.